LeetCode Basic Calculator II
Analyze and evaluate string-based mathematical expressions with stack logic
12
Stack Depth Visualization
This chart represents the value of elements stored in the stack during calculation.
| Step | Char | Last Op | Num | Stack Action |
|---|
What is LeetCode Basic Calculator II?
The leetcode basic calculator ii is a classic algorithmic challenge found on the LeetCode platform (Problem #227). It tasks developers with implementing a basic calculator to evaluate a string expression containing non-negative integers and basic operators: addition (+), subtraction (-), multiplication (*), and division (/).
This problem is a cornerstone for learning about string expression evaluation and how computers interpret mathematical syntax. Unlike simpler calculators, the leetcode basic calculator ii requires strict adherence to the mathematical order of operations (MDAS – Multiplication, Division, Addition, Subtraction), even though it does not involve parentheses.
Who should use this tool? Competitive programmers, computer science students, and software engineers preparing for technical interviews find the leetcode basic calculator ii logic essential for mastering stack-based parsing and linear time complexity algorithms.
leetcode basic calculator ii Formula and Mathematical Explanation
The logic behind solving leetcode basic calculator ii revolves around a single-pass algorithm using a stack. Because multiplication and division have higher precedence than addition and subtraction, we must delay the evaluation of the latter until we confirm no higher-precedence operations follow.
Step-by-Step Algorithm Derivation:
- Initialize a stack to store processed numbers.
- Iterate through the string, parsing multi-digit numbers.
- Keep track of the “last seen” operator (defaults to ‘+’).
- When an operator or the end of the string is reached:
- If the last operator was ‘+’, push the current number to the stack.
- If ‘-‘, push the negative of the current number.
- If ‘*’, pop the top of the stack, multiply it by the current number, and push the result back.
- If ‘/’, pop the top of the stack, divide it by the current number (integer division), and push the result back.
- The final result is the sum of all elements in the stack.
Variable Table
| Variable | Meaning | Data Type | Role |
|---|---|---|---|
s |
Input string | String | Contains digits and operators |
stack |
Processing container | Array/Stack | Stores intermediate values for addition |
currentNum |
Current parsed integer | Integer | Accumulates digits like ‘1’ and ‘2’ into 12 |
lastOp |
Previous operator | Character | Determines how currentNum enters the stack |
Practical Examples (Real-World Use Cases)
Example 1: High Precedence at the End
Expression: 3 + 2 * 2
- Process ‘3’:
lastOpis ‘+’, push 3. Stack: [3]. - Process ‘2’:
lastOpis ‘+’, push 2. Stack: [3, 2]. - Process ‘*’: Current operator is ‘*’, next number is 2. Pop 2, multiply by 2, push 4. Stack: [3, 4].
- Final Result: 3 + 4 = 7.
Example 2: Handling Integer Division
Expression: 10 - 5 / 2
- Process ’10’: Push 10. Stack: [10].
- Process ‘-‘: Next number is 5.
lastOpbecomes ‘-‘. - Process ‘/’: Next number is 2. Since
lastOpwas ‘/’, pop 5, divide by 2 (integer division = 2), push -2. Stack: [10, -2]. - Final Result: 10 + (-2) = 8.
How to Use This leetcode basic calculator ii Calculator
- Enter Expression: Type your mathematical string into the input box. You can use spaces as the calculator automatically ignores them.
- Real-time Validation: The calculator updates as you type. If you enter an invalid character, an error message will appear.
- Review the Stack: Look at the “Stack State” in the intermediate values section to see how the numbers were processed.
- Analyze the Steps: Consult the trace table to see exactly what happened at every character index. This is vital for understanding the leetcode basic calculator ii logic.
- Export Results: Click “Copy Results” to save the calculation for your documentation or code comments.
Key Factors That Affect leetcode basic calculator ii Results
- Operator Precedence: Multiplication and division must be handled immediately by modifying the stack’s top element, while addition/subtraction are deferred.
- Whitespace Handling: The leetcode basic calculator ii requires ignoring spaces, which can exist anywhere in the string.
- Integer Division: In many languages (and the LeetCode prompt), division must truncate toward zero. Our tool follows this standard.
- Multi-digit Integers: The algorithm must correctly combine consecutive characters (e.g., ‘1’, ‘0’, ‘0’) into a single integer (100).
- Stack Depth: The space complexity is O(n). While rare in simple expressions, very long strings of additions can lead to significant stack memory usage.
- Execution Order: The algorithm reads from left to right. Even though multiplication happens first logically, the parser reads every character in sequence once.
Frequently Asked Questions (FAQ)
eval() is generally prohibited as it bypasses the need to demonstrate knowledge of stack-based parsing and order of operations algorithm design.Related Tools and Internal Resources
- Comprehensive String Parsing Guide: Learn the basics of character-by-character iteration.
- Algorithm Efficiency Calculator: Analyze O(n) vs O(log n) performance.
- Data Structures: Stack Tutorial: A deep dive into LIFO principles.
- Postfix (Reverse Polish) Notation Converter: Convert infix expressions for easier calculation.
- Coding Interview Preparation: Roadmap for acing algorithmic interviews.
- Complexity Analysis Tools: Visualize space and time growth.