How To Calculate Thermally Choked Flow






How to Calculate Thermally Choked Flow | Rayleigh Flow Calculator


How to Calculate Thermally Choked Flow

Advanced Rayleigh Flow Analysis & Heat Addition Calculator


The initial Mach number of the gas flow.
Please enter a Mach number between 0.01 and 5.


Stagnation temperature at the duct entry.
Temperature must be greater than 0.


Amount of thermal energy added to the flow.


Ratio of specific heats (e.g., 1.4 for air).


Flow Status

Normal Flow

Exit Mach (M₂):
Exit T₀₂: K
Max T₀*: K
Max Heat (q_max): kJ/kg

*Calculation based on Rayleigh Flow relations. Thermally choked flow occurs when heat addition pushes the Mach number to exactly 1.0.

Rayleigh Flow Heating Curve (T₀/T₀* vs Mach)

Mach Number (M) T₀ / T₀* Inlet (M₁) Exit (M₂)

Visual representation of how stagnation temperature changes with Mach number during heat addition.

What is Thermally Choked Flow?

How to calculate thermally choked flow is a fundamental skill in gas dynamics and high-speed aerodynamics. Thermally choked flow occurs when heat is added to a gas moving through a constant-area duct, causing the flow to reach sonic conditions (Mach 1.0) at the exit. This phenomenon is governed by Rayleigh Flow principles.

Engineers must understand how to calculate thermally choked flow because once a flow becomes choked, no further heat can be added without physically altering the upstream (inlet) conditions. It is a critical limiting factor in the design of combustion chambers, afterburners, and nuclear thermal rockets. Many beginners mistakenly assume that adding more heat will simply increase the exit velocity indefinitely; however, the physics of compressibility dictates a “thermal ceiling” where the flow simply cannot accommodate more energy in its current state.

How to Calculate Thermally Choked Flow: Formula and Explanation

The mathematical foundation for understanding how to calculate thermally choked flow lies in the Rayleigh line equations. We define a reference state, denoted by an asterisk (*), which represents the state where the Mach number is exactly 1.0.

Variable Meaning Unit Typical Range
M Mach Number Unitless 0.1 – 3.0
T₀ Stagnation Temperature Kelvin (K) 200 – 3000
γ Specific Heat Ratio Unitless 1.3 – 1.67
q Heat Addition kJ/kg 0 – 2000
cₚ Specific Heat (Constant Pressure) J/kg·K ~1005 (Air)

The Primary Governing Equation

To determine the state of the flow, we use the ratio of stagnation temperature to the maximum possible stagnation temperature at M=1:

T₀ / T₀* = [ 2(γ + 1) M² (1 + (γ-1)/2 * M²) ] / (1 + γM²)²

When you seek to understand how to calculate thermally choked flow, you follow these steps:

  • Determine the inlet Mach number ($M_1$) and stagnation temperature ($T_{01}$).
  • Calculate $T_0^*$ using the formula above.
  • Calculate the new stagnation temperature $T_{02} = T_{01} + q/c_p$.
  • If $T_{02} > T_0^*$, the flow is thermally choked.

Practical Examples of How to Calculate Thermally Choked Flow

Example 1: Subsonic Combustion

Consider air entering a duct at $M_1 = 0.3$ and $T_{01} = 300 K$. You add 500 kJ/kg of heat. Using the Rayleigh relations, you find that $T_0^*$ is much higher than the resulting $T_{02}$. Thus, the flow speeds up to roughly $M_2 = 0.55$. In this case, the flow is not choked, and you can add more heat until $M_2$ reaches 1.0.

Example 2: Reaching the Choking Limit

Imagine a supersonic inlet at $M_1 = 2.0$ and $T_{01} = 400 K$. Adding heat to a supersonic flow actually decreases the Mach number. If you add enough heat to force the Mach number down to 1.0, any additional heat addition will cause a shock wave to form or change the inlet mass flow rate, as the duct is now thermally choked.

How to Use This Thermally Choked Flow Calculator

  1. Enter Inlet Mach: Input the starting speed of your gas relative to the speed of sound.
  2. Set Stagnation Temp: Provide the total temperature at the start of the heating section.
  3. Define Heat Addition: Enter the amount of energy (in kJ/kg) being transferred to the fluid.
  4. Check Status: Observe the “Flow Status”. If it says “CHOKED”, your heat input exceeds the physical capacity of the duct at that inlet condition.
  5. Analyze the Chart: The red dot shows your inlet, and the green dot shows the exit. If they merge at the peak, you are at the choking point.

Key Factors That Affect Thermally Choked Flow

  • Inlet Mach Number: The closer $M_1$ is to 1.0, the less heat is required to reach a choked state.
  • Specific Heat Ratio (γ): Different gases (like Argon vs. Steam) react differently to heat addition due to their molecular structure.
  • Gas Constant (R): Affects the $c_p$ value, determining how much the temperature rises for a given amount of heat.
  • Mass Flow Rate: While not in the Rayleigh ratio directly, it determines the total power required for choking.
  • Flow Regime: Subsonic flows accelerate with heat; supersonic flows decelerate with heat. Both move toward Mach 1.0.
  • Duct Area: Rayleigh flow assumes a constant area. If the area changes, you must use combined flow functions.

Frequently Asked Questions

1. What happens if I add heat beyond the choking limit?

If you attempt to add more heat than $q_{max}$, the flow will “adjust.” In subsonic flows, the inlet mass flow rate usually decreases. In supersonic flows, a shock wave may propagate upstream to change the inlet Mach number.

2. Does thermally choked flow only happen in supersonic speeds?

No, it happens in both subsonic and supersonic flows. Both regimes move toward Mach 1.0 when heat is added.

3. How does friction affect these results?

This calculator uses Rayleigh Flow, which assumes zero friction. Real-world ducts involve Fanno Flow (friction) and Rayleigh Flow (heat) simultaneously, which is much more complex.

4. Why does temperature decrease in some Rayleigh flows?

Interestingly, for subsonic flows between Mach $1/\sqrt{\gamma}$ and 1.0, adding heat increases stagnation temperature but can actually decrease static temperature.

5. Is this used in jet engine design?

Absolutely. Designing afterburners requires knowing how to calculate thermally choked flow to ensure the nozzle doesn’t cause the engine to surge.

6. What is the unit of heat addition?

We typically use kJ/kg (kilojoules per kilogram) to represent energy added per unit mass of the working fluid.

7. Can cooling un-choke a flow?

Yes, removing heat (cooling) moves the Mach number away from 1.0, effectively increasing the margin before choking occurs.

8. Does the gas constant R change?

For most engineering calculations, R is assumed constant unless the gas undergoes a chemical change or dissociation at very high temperatures.

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